1760. Check Array Formation Through Concatenation
My accepted Python solution to LeetCode problem 1760, Check Array Formation Through Concatenation, running in 0ms.
- Difficulty: Easy
- Python
- Runtime 0ms
- Memory 17.2MB
- Updated
Read the problem on LeetCode View on GitHub
The problem statement is LeetCode’s and stays on their site. What follows is my accepted solution.
Python
Accepted on LeetCode — runtime 0ms, memory 17.2MB, accepted 2025-12-30.
class Solution:
def canFormArray(self, arr: List[int], pieces: List[List[int]]) -> bool:
piece_map = {p[0]: p for p in pieces}
i = 0
while i < len(arr):
if arr[i] not in piece_map:
return False
piece = piece_map[arr[i]]
for val in piece:
if i >= len(arr) or arr[i] != val:
return False
i += 1
return True